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Subject:Re: Checking for duplicates
Date:Fri, 20 May 2016 14:55:52 +1000
From:Tom Krieg <invalid@nodomain.tv>
Newsgroups:pnews.paradox-client_server
Never mind. I just went through this again after writing it all down and 
there is an obvious error in my logic.

Step 4 should have been:

SELECT foo.locality_uid, COUNT(1) as COUNT
FROM (SELECT DISTINCT address_detail.address_postcode,
                       address_detail.locality_uid
       FROM address_detail) AS foo
GROUP BY foo.locality_uid
HAVING COUNT(1) > 1

I found them all.


On 20/05/2016 2:49 PM, Tom Krieg wrote:
> So we have a number of localities with more than 1 postcode. Now I want
> to determine which ones.
>
> Step 4: Check for duplicate postcodes.
>
> SELECT foo.address_postcode, foo.locality_uid, COUNT(1) as COUNT
> FROM
>     (SELECT DISTINCT address_detail.address_postcode,
>                      address_detail.locality_uid
>      FROM address_detail) AS foo
> GROUP BY foo.address_postcode, foo.locality_uid
> HAVING COUNT(1) > 1
> ;
>
> 0 Rows
>


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